Jon Moxley Confirmed For AEW Debut TNT Show

Jon Moxley Confirmed For AEW Debut TNT Show

All Elite Wrestling (AEW) has confirmed that Jon Moxley will be appearing on their debut TNT show on Wednesday, October 2.

As reported previously, the first match announced for the show is AEW Executive President Cody vs. Sammy Guevara.

While this was obviously going to happen, AEW has now made an official announcement, and will be hoping that this announcement boosts ticket sales when they go on sale this Friday (August 2).

Tickets will cost $250 (within the first three rows of floor ringside sections, seat location includes an AEW-designed commemorative take-home chair once the event is over), $90, $75, $50, $35, and $20.

Moxley’s next match for the promotion will be at All Out on August 31, where he takes on Kenny Omega in what could be one of the matches of the year.

Stay tuned to for more updates on the show’s premiere, as it is believed the name of the show will be announced this week as well as other names and matches for the show.


5 years ago by Andy Datson


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